<pre>
<pre>
 n=     2          3          4          5          6
    (8,4)      (9,7)      (9,3)     (10,7)     (11,7)

   aijklm     abcde?     acdefg     abcde?     abkmuz
   bijklm     fghij?     bhijkl     fghij?     bcpwy?
   cnopqr     klmno?     cmnopq     klmno?     cdlnvz
   dnopqr     pqrst?     dhnrvy     pqrst?     deqxu?
   estuvw     uvwxy?     eiosvw     uvwxy?     efmowz
   fstuvw     afkpu?     fjptwx     afkpu?     fgryv?
   gxyz??     bglqv?     gkquxy     bglqv?     ghnkx?
   hxyz??     chmrwz     lmrstu     chmrwz     hisuw?
              dinsxz     zab???     dinsxz     ijoly?
                                    ejotyz     jatvx?
                                               pqrstz
</pre>

I think I can prove that there is no solution with 11 dice with 9
don't cares or with 10 dice, but I haven't checked all the details, so
I might have made a mistake.  In any case, that leaves open the case
of 11 dice with 8 don't cares; my guess is that it is not possible.

-- John Rickard (jrickard@eoe.co.uk)
</pre>
