<pre>
<pre>
 ---------------
 B   /  .......||..B/sin(theta)
    theta      ||
 ---||-----X     ||
	  ||    ||
	  || ...||..A/cos(theta)
	  ||    ||
	  ||    ||
	  || A  ||
</pre>


Theta is the angle off horizontal.

Minimize length = A/cos(theta) + B/sin(theta)

<pre>
    d(length)/d(theta)
	   = A'''sin(theta)/cos(theta)^2 - B'''cos(theta)/sin(theta)^2 (?)
	   = 0
    A'''sin(theta)/cos(theta)^2 = B'''cos(theta)/sin(theta)^2

    B/A <code> sin(theta)^3/cos(theta()^3 </code> tan(theta)^3

    theta = inverse''tan(cube''root(B/A))
</pre>

If you use the trigonometric formulas  cos^2 x = 1/(1 + tan^2 x)
and  sin x = tan x cos x, and plug through the algebra, I believe
that the formula for the length reduces to

(A^(2/3) + B^(2/3))^(3/2)

At any rate this is symmetric in A and B as one would expect, and
has the right values at A=B and as either A-->0 or B-->0.
</pre>
