<pre>
<pre>
 x<code>1        y</code>
 x<code>1151     y</code>120
 x<code>2649601  y</code>276240
 etc.
</pre>

Each successive solution is about 2300 times the previous
solution;  they are every 8th partial fraction (x=numerator,
y<code>denominator) of the continued fraction for sqrt(92) </code>
<pre>
 ~[[9,  1,1,2,4,2,1,1,18,  1,1,2,4,2,1,1,18,  1,1,2,4,2,1,1,18, ...]]
</pre>

Once you have the smallest positive solution (x1,y1) you
don't need to "search" for the rest.  You can obtain the nth positive
solution (xn,yn) by the formula

(x1 + y1 sqrt(92))^n = xn + yn sqrt(92).

See Niven & Zuckerman's An Introduction to the Theory of Numbers.
Look in the index under Pell's equation.
</pre>
